NYCPHP Meetup

[selyah]

hello:
i looked at that link before and i think that i was entering it that way, yet i am still getting that warning.......should the function be declared somewhere before?

"Ben Sgro (ProjectSkyLine)" <ben at projectskyline.com> wrote:       Hello, 
  
 According to php.net:
 http://us2.php.net/manual/en/function.scandir.php
 scandir
 (PHP 5)
 Is only available in php5.
  
 - Ben
   

 Ben Sgro, Chief Engineer
ProjectSkyLine - Defining New  Horizons

 Our company: www.projectskyline.com
Our products:  www.project-contact.com
  
 This e-mail is confidential information intended only for the use of the  individual to whom it is addressed.
    ----- Original Message ----- 
   From:    selyah 
   To: talk at lists.nyphp.org 
   Sent: Sunday, July 29, 2007 2:35 PM
   Subject: [nycphp-talk] alternate to    scandir()
   

I am currently using PHP version 4.3.10 and need a bit of    help.  I created a script to display images in a directory.  part of    the script is shown here    :

$dir=$_SERVER['DOCUMENT_ROOT']."coles/admin/new_images/".$_FILES['image']['name'];
$files=scandir($dir);

this    opens the directory and an returns an array of files and directories found    within the folder.  The array is assigned to $files.

the problem    is that when i execute the file, i am getting this  warning:

"Call    to undefined function: scandir()...."    and points to this    line: $files=scandir($dir);

is there an alternate syntax to writing    this function call in version 4.3.10? and wher can i find a link to a manual    for this version?
thanks
      

---------------------------------
    
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